The aim of this investigation is to extract as much information as possible from the results given to us from an experiment.DiagramBelow is a diagram showing how I expect the apparatus was set up for the experiment. I have also written a list of some of the apparatus I expected was used.Palm Top RampTrolley BlockLight Gate G-ClampTrolleyLight Gate122cm2.

5cm1.9cm BlockRampMethodThe apparatus was set up as shown above and illustrates a runaway vehicle down a hill. The light gate was placed at several points along the slope and measured the time taken for the card, of length 3cm, to pass through it.The trolley, of mass 623g, was released 122cm up the slope from front of the card. This was done accurately by using a set square to line up the front of the card with the 122cm mark on the ramp. Once this had been achieved the set square was moved away and the trolley went down the ramp.

The set square ensured the trolley was not pushed forwards but only moves down the slope due to its own accord. The palm top then measured the time it took for the whole piece of card to pass through the light gate.Once this was done the light gate was moved down the slope by 10cm at a time and again recorded the time it took for the card to pass through the light gate. This was carried out for 8 different locations.

Each location’s time was repeated to end up with 5 readings. The average of these could then be taken and used as the time it took for the card to pass through the light gate.Preliminary GraphThe graph above shows that as the slope distance increases the velocity of the trolley must increase.

This can be seen in the fact that the time it takes to pass through the light gate decreases. It can also be said that there is a greater change in velocity at the start of the ramp than at the end, which can be seen due to the fact that the gradient becomes shallower. This must mean that there is a larger force opposing the trolley as it picks up speed and could be due to air resistance.Going about the InvestigationsIn order to calculate velocity and other such information about the trolley I will use the SUVAT equations as well as Newton’s Second Law. This will enable me to make sense of the data that I am provided with, which includes the time it takes for the card to pass through the light gate and the slope distance.

Below are shown the formulae I will use.a = Accelerationv = Final Velocityu = Initial Velocitys = Distancet = Time1. a = (v-u)/ t2. v2 = u2 + 2as3. s = ut + 1/2at24. s = 1/2(v + u)t5.

v = u + atAs well as this I can use Newton’s Second Law to Model the Particle, in order to find out friction etc.Newton’s second law states, ‘The Force, F, applied to a particle is proportional to the mass, m, of the particle and the acceleration produced.’This can then be represented by the equation F=maIn order to model the trolley I must know the acceleration. I will therefore use the SUVAT equations first.Using the SUVAT equationsFirstly I will calculate the velocity of the card through the light gate using the formula:(First Light Gate)Speed = Distance / Time= 0.

03 / 0.15544 (the card is 3cm long = 0.03m)= 0.193I will now do this for all the light gate positions.Next I shall work out the time for the card to reach the light gate by rearranging the equation:S = 1/2 (v + u)tTherefore 2s = (v + u)tT = 2s / v (as initial velocity is always zero)Therefore for the first light gate the trolley takes:T = 0.

2 / 0.193= 1.03sI can now do this for all the other light gate positions also.I can now work out the acceleration of the trolley through the light gate by using the formula:A = (v – u) / tFor the first light gateA = 0.

193 / 1.03= 0.186ms-2I will now apply this equation for all the other light gate positions.Now that I have acceleration for the trolley I can model it as a particle going down a slope and find out the model acceleration.

This value can then be subtracted from the actual value to give resistance to the path of the trolley.Modelling the TrolleyThe Trolley can be modelled as a right angle triangle and thus further information can be found out such as the angle of the slope and then consequently the friction can be found out.122cm2.5cmAngle ?Working out the angleIf Sin ? = 2.

5/122Therefore ? = sin-1 (2.5/122)= 1.17*Therefore the angle of the slope is 1.17 degrees.Using this I can now work out what the acceleration of the model is.

This should be greater than the values I obtained using the SUVAT formulas as I am not taking into account friction etc.Rï¿½NMgsin?Perpendicular to the Slope : Mgcos? = R(0.623 x 9.8) cos 1.17 = NTherefore R = 6.

104NI can now calculate the friction along the slope at various distances down the slope. This is the overall resistance to the driving force of the trolley, so can include air resistance.Along the Slope: F = Mgsin? – ï¿½R where F is total driving forceAt 0.1m down slope ma = Mgsin? – ï¿½R0.116 = 0.125 – 6.104ï¿½8.6 x 10-3 = 6.

104ï¿½Therefore ï¿½ = 1.41 x 10-3At 0.8m down the slope F = Mgsin? – ï¿½RMa = Mgsin? – ï¿½R0.095 = 0.125 – ï¿½6.1040.03 = 6.

104ï¿½Therefore ï¿½ = 5 x 10-3Using this formula I have calculated the friction for all the other distances and is shown in the results table.As well this I can calculate the gravitational potential energy and the kinetic energy. I will then be able to take the kinetic energy away from the gravitational potential energy to work out the energy lost in the form of sound, heat etc. Below is shown two examples of each.Kinetic Energy = 1/2mv2At 0.1m down the slope: KE = 1/2 x 0.623 x 0.

1932= 0.0116JAt 0.8m down the slope: KE = 1/2 x 0.

623 x 0.2672= 0.0222JGravitational Potential Energy = Mass x Velocity x HeightIn order to work out the gravitational potential energy I must use trigonometry to calculate the height of the trolley at certain light gates. For simplicity only two examples are shown below. The others are shown in the results table later on.At 0.1m down the slope:112cmxAngle ? = 1.

17 degreesIf sin ? = x / 112Then x = 112 sin ?= 2.29cm (2d.p.)Therefore I can now calculate the gravitational potential energy of the trolley at the first light gate.GPE = Mass x Gravity x Height (in metres)= 0.623 x 9.8 x 0.0229= 0.

140JAt 0.8m down the slope:42cmyAngle ? = 1.17 degreesIf sin ? = y / 42Then y = 42 sin ?= 0.86cm (2 d.p.)Therefore GPE = Mass x Gravity x Height= 0.

623 x 9.8 x 0.0086= 0.053JSources of ErrorMeasuring the distance from where the trolley is released was a source of error in the experiment. If the trolley was released slightly in front or behind from where it should have been released from, this would cause the time for the card to pass through the light gate to differ.As well as this the card may have hit the light gate causing it to drastically slow down and therefore cause the time taken for it to pass through the light gate to increase. This would further have an impact on the rest of the experiment because the shape of the card may have been modified upon collision-E.

g. initially the length of the card which the light gate is measuring would be 3cm. If, however, it then crashes, the shape of the card would be distorted. The point at which the light gate is measuring the time for the card to pass through the light gate may then increase as the card has crumpled and so it longer in length and vice versa.We must also consider the fact that at some point the slope may have slightly slipped, causing the gradient of the slope to change. This would obviously greatly affect the rate of acceleration of the trolley and produce inaccurate results.

There are therefore many sources of error in this procedure which must be accounted for in the experiment.The results from my experiment are shown in the tables in the following pages, as well as explanations of the graphs I have drawn.AnalysisGraph 1: Comparing Actual Velocity of Trolley as it goes down the slopeFrom the graph you can see that as the trolley goes down the hill it picks up speed. The greatest change increase in velocity occurs at the top of the slope and can be described due to the fact that at this point is has the most GPE to convert to KE.As the trolley goes down the slope, however, it is clear that the velocity increase is not proportional to the distance it travels. This can be accounted for due to the friction I have calculated.

However this remains constant so there must be another factor involved. It must therefore be air resistance as this increases as you go faster. Therefore as the trolley picks up speed, it is slowed down more until it reaches its terminal velocity.I chose to do this graph as it is a visual aid in seeing how the trolley changes in speed through its course.Graph 2: Graph showing how the long it takes for the trolley to go down the slope to various distancesThe graph shows an almost proportional trend in that as the distance increases so does the time it takes for the trolley to go this distance. There is however a slight curve towards the end. This can be accounted for in that the trolley has more air resistance as it goes down the slope, so the time it takes must increase.

Therefore the rate must slow, so the graph starts to level out. However it seems that the trolley reaches its terminal velocity reasonably quickly as the rate is almost constant.Graph 3: Graph showing how the Kinetic Energy of the trolley changes as it goes down the slopeThe graph shows as that as the trolley goes further down the slope, its kinetic energy increases. This is very easy to explain in that as it moves down the slope it picks up more speed. The equation for kinetic energy is KE = 1/2mv2.

The mass of the particle does not change and so the rise in kinetic energy is solely due to the trolley increasing in speed. When it is higher up the slope, it has more gravitational potential energy so it can not posses as much kinetic. Lower down the slope it has less GPE so it can posses more KE.Graph 4: Graph to show how the Gravitational Potential Energy of the trolley changes as it goes down the slopeThe graph shows that as the trolley goes further down the slope it has less gravitational potential energy. This is also easy to explain in that when it is at the top of the ramp it has more height. Since GPE = mgh, the more height it has the more GPE it shall have. As it moves down the slope it is not as high up, so it has less GPE.Graph 5: Comparing GPE with KEThis graph basically illustrates the connection between GPE and KE.

It shows that when one increases the other must decrease. Using this graph and plotting interpolation lines and then using the GPE against distance graph one can work out the position of the trolley at a given location.